Assignment 3 - Extra Credit: Option 3

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Prof. Sandra Bloomwicks
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Postby Prof. Sandra Bloomwicks » Sun Feb 16, 2014 8:36 am

I'll start you guys off with the first sequence. Solve the sequence above yours and post the rule/equation for it as well as the next 3 numbers. Then create your own sequence with at least the first 5 numbers and post it in the same reply.

Sequence:
-3, 0, 9, 36, 117
Last edited by Prof. Sandra Bloomwicks on Sun Feb 16, 2014 8:46 am, edited 1 time in total.
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Will Lestrange
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Postby Will Lestrange » Sun Apr 06, 2014 7:48 pm

Sandra Bloomwicks wrote:
QUOTE (Sandra Bloomwicks @ Feb 16 2014, 01:36 AM) <{POST_SNAPBACK}>
I'll start you guys off with the first sequence. Solve the sequence above yours and post the rule/equation for it as well as the next 3 numbers. Then create your own sequence with at least the first 5 numbers and post it in the same reply.

Sequence:
-3, 0, 9, 36, 117

Rule: f(n) = f(n - 1) + 3^(n - 1) (alternatively, f(n) = (3^n - 9)/2)
Next three numbers: 360, 1089, 3276

New sequence:
50, 33, 25, 20, 17, 14, 13
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Shiloh Adlar
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Postby Shiloh Adlar » Sun Jun 15, 2014 8:09 am

Will Lestrange wrote:
QUOTE (Will Lestrange @ Apr 6 2014, 12:48 PM) <{POST_SNAPBACK}>
Rule: f(n) = f(n - 1) + 3^(n - 1) (alternatively, f(n) = (3^n - 9)/2)
Next three numbers: 360, 1089, 3276

New sequence:
50, 33, 25, 20, 17, 14, 13

Rule: They are decimal fractions rounded up without the decimal point so 1/2 = 0.50, 1/3 = 0.33, 1/4 = 0.25, 1/5 = 0.20 and so on.
The next three numbers would be 11, 10, 9.

New Sequence:
1, 3, 23, 229, 2869, 43531
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Re:

Postby Kathren Johnsun » Fri Apr 17, 2015 1:38 am

Shiloh Adlar wrote:Rule: They are decimal fractions rounded up without the decimal point so 1/2 = 0.50, 1/3 = 0.33, 1/4 = 0.25, 1/5 = 0.20 and so on.
The next three numbers would be 11, 10, 9.

New Sequence:
1, 3, 23, 229, 2869, 43531


Rule: (n+1)^(n+1)-n^n, so 2^2-1^1=3, 3^3-2^2=23, 4^4-3^3=256-27=229 . . . the next three numbers would be 776887, 15953673, 370643273.

New Sequence:
5, 17, 53, 161, 485

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Lamia Brickley
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Re: Assignment 3 - Extra Credit: Option 3

Postby Lamia Brickley » Sat Jun 13, 2015 10:55 pm

Kathren Johnsun wrote:New Sequence:
5, 17, 53, 161, 485


Rule: (n*3)+2
next numbers would be: 1457, 4375, 13121

New sequence:
-2, 4, -8, 16, -32
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